And then, for the three-team tie, there's this. I hope I'm interpreting everything correctly. • If Club 1 and 2 have identical records against one another, but each has a better record against Club 3, then Clubs 1 and 2 would follow the two-Club tiebreak rules to break their tie to pick the first designation. The Mets and Cardinals are both 4-3 against the Giants, and 3-3 against each other, so in this scenario the Giants are Club 3. Since the Cardinals win the tiebreaker against the Mets, they'd be Club 1. Three-Club Tie for Two Wild Card Spots: After Clubs have been assigned their A, B and C designations, Club A would host Club B. The winner of the game would be declared one Wild Card winner. Club C would then host the loser of the game between Club A and Club B to determine the second Wild Card Club. So the Cardinals are Club A, the Mets are Club B, and the Giants are Club C. The Mets would play the Cardinals on Monday in St. Louis. If they win, they get Tuesday off while the Giants and Cardinals play each other. If the Cardinals win, the Mets stay in St. Louis to play Wednesday's Wild Card game. If the Giants win, both teams fly to New York to play Wednesday's game at Citi Field. If the Mets lose Monday's game, they're not eliminated. They'd go to San Francisco* to play the Giants on Tuesday, and if they win they'd fly back to St. Louis to play Wednesday's Wild Card game. * I would have guessed that this game would be played in New York, but the rule does say that Club C would be the host.