The Post does a nice job of explaining what would happen: If the Mets are in a three-way tie for the two wild card spots … The three teams choose or receive A, B and C designations, determined by the tiebreakers enumerated above. It is assumed the Cardinals and Mets, owning the head-to-head edge over the Giants, would choose the designations that give them two chances to make the postseason. In that case, on Monday, Oct. 3, the Cardinals (team A) would host the Mets (team in the first game. The winner of the game advances to the playoffs as the host team in the Wild Card Game. On Tuesday, Oct. 4, the loser of that game would travel to face the Giants (team C) in San Francisco. The winner of that game earns the second wild card and becomes the road team in the Wild Card Game the following day. So here’s the most dramatic scenario that conceivably awaits the Mets: They close the regular season on Oct. 2 in Philadelphia, and it results in a three-way wild-card tie. They play in St. Louis on Oct. 3 — and lose. They play in San Francisco on Oct. 4 — and win. They play in St. Louis again on Oct. 5 for the Wild Card game. I'm assuming that the October 3 and 4 games would be officially regular season games, which means that the Mets (or Giants or Cardinals) could potentially have a 164-game season.